 20 Students Graduates and under graduates were enrolled in a maths course. Their ages were 18, 19, 19, 19, 19,20,20,20,20,20,21,21,21,21,22,23,24,27,30,36

Find the median age of all students.

Find the median age of all students under 25 years

Find the mode age of all students

Find the mean age of all students

Two more students enter the class. Age of both students is 19. What is the mean, median and mode now?
Answers:
age<c(18,19,19,19,19,20,20,20,20,20,21,21,21,21,22,23,24,27,30,36)
median(age)
[1] 20.5
age[age<25]
[1] 18 19 19 19 19 20 20 20 20 20 21 21 21 21 22 23 24
median(age[age<25])
[1] 20
n=table(age)
n
age
18 19 20 21 22 23 24 27 30 36
1 4 5 4 1 1 1 1 1 1
mod<which(n==max(n));
> mod 20 3
mean(age)
[1] 22
age<c(age,19,19)
median(age)
[1] 20
mean(age)
[1] 21.72727
n=table(age)
> n age 18 19 20 21 22 23 24 27 30 36 1 6 5 4 1 1 1 1 1 1
mod<which(n==max(n))
> mod 19 2
The screen shot of the following program is given below
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